22.2.11

SOLUTION STOICHIOMETRY. Feb 22

Today we learned about Solution Stoichiometry!


H2O = A universal solvent
  • Solutions are homogeneous(composed of similar or identical parts or elements) mixtures
  • Homogeneous mixtures are composed of a SOLUTE and a SOLVENT
  • A Solute is the chemical present in lesser amount (dissolved)
  • A Solvent is the chemical present in the greater amount (whatever does the dissolving)
  • CHEMICALS DISSOLVED IN WATER ARE AQUEOUS! ie. H2SO4(aq) ---> dissolved in H2o. How much? This is the CONCENTRATION
Basically, molarity is MOLES/ VOLUME
MOL/L = M (MOLARITY)

Getting it? Good.

Examples: 
DETERMINE THE CONCENTRATIONS OF THE SOLUTIONS BELOW:

a) 0.118 mol of water in 2.50 L
0.118 mol
2.50 L 

= 4.7 x 10^-2 M or mol/L

b) 12.5 g of PbCl2 in 30 mL of water
*First change grams into moles, than change mL into L, than take your moles and divide by your amount of liters!

   12.5 g x 1 mol = 0.0448 mol
278.2 g  
                             30 mL x 1 L = .03 L
                                    1000mL
SOLUTION: 0.0448 mol
          .03 L
= 1.49 M
= 1.5 M

Now lets crank up the chemistry and do so more difficult questions!

How many litres of solution are required to make the following solutions?

a) 0.250 mol dissolved to create a 1.75 M solution of Na2S

0.25 mol x 1 L = 0.143 L
  1.75 mol
*for these types of equations, you can flip mol/L to become L/mol since you're trying to find L!

b) 35.0 g of I2 used to create a 0.150 M solution
35.0 g x 1mol = .138 mol x   1L    = .919 L
253.8g            0.150 M

Pretty easy stuff no?? HERE IS A VIDEO TO HELP EXPLAIN TO YOU THE CONCEPT OF MOLARITY IF YOU'RE HAVING SOME TROUBLE! Go around the 4 minute mark because the guy sneezes haha...LOL!


Post by Ren Flores

No comments:

Post a Comment